494. Target Sum
Description
You are given an integer array nums
and an integer target
.
You want to build an expression out of nums by adding one of the symbols '+'
and '-'
before each integer in nums and then concatenate all the integers.
- For example, if
nums = [2, 1]
, you can add a'+'
before2
and a'-'
before1
and concatenate them to build the expression"+2-1"
.
Return the number of different expressions that you can build, which evaluates to target
.
Example 1:
Input: nums = [1,1,1,1,1], target = 3 Output: 5 Explanation: There are 5 ways to assign symbols to make the sum of nums be target 3. -1 + 1 + 1 + 1 + 1 = 3 +1 - 1 + 1 + 1 + 1 = 3 +1 + 1 - 1 + 1 + 1 = 3 +1 + 1 + 1 - 1 + 1 = 3 +1 + 1 + 1 + 1 - 1 = 3
Example 2:
Input: nums = [1], target = 1 Output: 1
Constraints:
1 <= nums.length <= 20
0 <= nums[i] <= 1000
0 <= sum(nums[i]) <= 1000
-1000 <= target <= 1000
Solutions
Solution: Dynamic Programming
- Time complexity: O(n*sum(nums))
- Space complexity: O(n+n*sum(nums))
JavaScript
js
/**
* @param {number[]} nums
* @param {number} target
* @return {number}
*/
const findTargetSumWays = function (nums, target) {
const n = nums.length;
const memo = new Map();
const buildExpression = (index, sum) => {
if (index >= n) return sum === target ? 1 : 0;
const key = `${index},${sum}`;
if (memo.has(key)) return memo.get(key);
const num = nums[index];
const plus = buildExpression(index + 1, sum + num);
const minus = buildExpression(index + 1, sum + num * -1);
const result = plus + minus;
memo.set(key, result);
return result;
};
return buildExpression(0, 0);
};