2059. Minimum Operations to Convert Number
Description
You are given a 0-indexed integer array nums
containing distinct numbers, an integer start
, and an integer goal
. There is an integer x
that is initially set to start
, and you want to perform operations on x
such that it is converted to goal
. You can perform the following operation repeatedly on the number x
:
If 0 <= x <= 1000
, then for any index i
in the array (0 <= i < nums.length
), you can set x
to any of the following:
x + nums[i]
x - nums[i]
x ^ nums[i]
(bitwise-XOR)
Note that you can use each nums[i]
any number of times in any order. Operations that set x
to be out of the range 0 <= x <= 1000
are valid, but no more operations can be done afterward.
Return the minimum number of operations needed to convert x = start
into goal
, and -1
if it is not possible.
Example 1:
Input: nums = [2,4,12], start = 2, goal = 12 Output: 2 Explanation: We can go from 2 → 14 → 12 with the following 2 operations. - 2 + 12 = 14 - 14 - 2 = 12
Example 2:
Input: nums = [3,5,7], start = 0, goal = -4 Output: 2 Explanation: We can go from 0 → 3 → -4 with the following 2 operations. - 0 + 3 = 3 - 3 - 7 = -4 Note that the last operation sets x out of the range 0 <= x <= 1000, which is valid.
Example 3:
Input: nums = [2,8,16], start = 0, goal = 1 Output: -1 Explanation: There is no way to convert 0 into 1.
Constraints:
1 <= nums.length <= 1000
-109 <= nums[i], goal <= 109
0 <= start <= 1000
start != goal
- All the integers in
nums
are distinct.
Solutions
Solution: Breadth-First Search
- Time complexity: O(1000n)
- Space complexity: O(1000)
JavaScript
/**
* @param {number[]} nums
* @param {number} start
* @param {number} goal
* @return {number}
*/
const minimumOperations = function (nums, start, goal) {
const visited = new Set();
let queue = [start];
let result = 0;
function isValidOperation(value) {
if (value < 0 || value > 1000) return false;
if (visited.has(value)) return false;
visited.add(value);
return true;
}
while (queue.length) {
const size = queue.length;
const nextQueue = [];
result += 1;
for (let index = 0; index < size; index++) {
const value = queue.pop();
for (const num of nums) {
const add = value + num;
const minus = value - num;
const xor = value ^ num;
if (add === goal || minus === goal || xor === goal) return result;
isValidOperation(add) && nextQueue.push(add);
isValidOperation(minus) && nextQueue.push(minus);
isValidOperation(xor) && nextQueue.push(xor);
}
}
queue = nextQueue;
}
return -1;
};