2140. Solving Questions With Brainpower
Description
You are given a 0-indexed 2D integer array questions
where questions[i] = [pointsi, brainpoweri]
.
The array describes the questions of an exam, where you have to process the questions in order (i.e., starting from question 0
) and make a decision whether to solve or skip each question. Solving question i
will earn you pointsi
points but you will be unable to solve each of the next brainpoweri
questions. If you skip question i
, you get to make the decision on the next question.
- For example, given
questions = [[3, 2], [4, 3], [4, 4], [2, 5]]
:- If question
0
is solved, you will earn3
points but you will be unable to solve questions1
and2
. - If instead, question
0
is skipped and question1
is solved, you will earn4
points but you will be unable to solve questions2
and3
.
- If question
Return the maximum points you can earn for the exam.
Example 1:
Input: questions = [[3,2],[4,3],[4,4],[2,5]] Output: 5 Explanation: The maximum points can be earned by solving questions 0 and 3. - Solve question 0: Earn 3 points, will be unable to solve the next 2 questions - Unable to solve questions 1 and 2 - Solve question 3: Earn 2 points Total points earned: 3 + 2 = 5. There is no other way to earn 5 or more points.
Example 2:
Input: questions = [[1,1],[2,2],[3,3],[4,4],[5,5]] Output: 7 Explanation: The maximum points can be earned by solving questions 1 and 4. - Skip question 0 - Solve question 1: Earn 2 points, will be unable to solve the next 2 questions - Unable to solve questions 2 and 3 - Solve question 4: Earn 5 points Total points earned: 2 + 5 = 7. There is no other way to earn 7 or more points.
Constraints:
1 <= questions.length <= 105
questions[i].length == 2
1 <= pointsi, brainpoweri <= 105
Solutions
Solution: Dynamic Programming
- Time complexity: O(n)
- Space complexity: O(n)
JavaScript
js
/**
* @param {number[][]} questions
* @return {number}
*/
const mostPoints = function (questions) {
const n = questions.length;
const dp = Array.from({ length: n }, () => -1);
const solveQuestion = index => {
if (index >= n) return 0;
if (dp[index] !== -1) return dp[index];
const skipPoints = solveQuestion(index + 1);
const [points, brainpower] = questions[index];
const solvePoints = points + solveQuestion(index + brainpower + 1);
const result = Math.max(skipPoints, solvePoints);
dp[index] = result;
return result;
};
return solveQuestion(0);
};