3074. Apple Redistribution into Boxes

Description

You are given an array apple of size n and an array capacity of size m.

There are n packs where the ith pack contains apple[i] apples. There are m boxes as well, and the ith box has a capacity of capacity[i] apples.

Return the minimum number of boxes you need to select to redistribute these n packs of apples into boxes.

Note that, apples from the same pack can be distributed into different boxes.

 

Example 1:

Input: apple = [1,3,2], capacity = [4,3,1,5,2]
Output: 2
Explanation: We will use boxes with capacities 4 and 5.
It is possible to distribute the apples as the total capacity is greater than or equal to the total number of apples.

Example 2:

Input: apple = [5,5,5], capacity = [2,4,2,7]
Output: 4
Explanation: We will need to use all the boxes.

 

Constraints:

• 1 <= n == apple.length <= 50
• 1 <= m == capacity.length <= 50
• 1 <= apple[i], capacity[i] <= 50
• The input is generated such that it's possible to redistribute packs of apples into boxes.

 

Solutions

Solution: Greedy

• Time complexity: O(nlogn)
• Space complexity: O(1)

 

JavaScript

/**
 * @param {number[]} apple
 * @param {number[]} capacity
 * @return {number}
 */
const minimumBoxes = function (apple, capacity) {
  const n = capacity.length;
  let apples = apple.reduce((sum, apple) => sum + apple);

  capacity.sort((a, b) => b - a);

  for (let index = 0; index < n; index++) {
    apples -= capacity[index];

    if (apples <= 0) return index + 1;
  }

  return -1;
};