1448. Count Good Nodes in Binary Tree
Description
Given a binary tree root
, a node X in the tree is named good if in the path from root to X there are no nodes with a value greater than X.
Return the number of good nodes in the binary tree.
Example 1:
Input: root = [3,1,4,3,null,1,5] Output: 4 Explanation: Nodes in blue are good. Root Node (3) is always a good node. Node 4 -> (3,4) is the maximum value in the path starting from the root. Node 5 -> (3,4,5) is the maximum value in the path Node 3 -> (3,1,3) is the maximum value in the path.
Example 2:
Input: root = [3,3,null,4,2] Output: 3 Explanation: Node 2 -> (3, 3, 2) is not good, because "3" is higher than it.
Example 3:
Input: root = [1] Output: 1 Explanation: Root is considered as good.
Constraints:
- The number of nodes in the binary tree is in the range
[1, 10^5]
. - Each node's value is between
[-10^4, 10^4]
.
Solutions
Solution: Depth-First Search
- Time complexity: O(n)
- Space complexity: O(Tree Deep)
JavaScript
js
/**
* @param {TreeNode} root
* @return {number}
*/
const goodNodes = function (root) {
const getGoodNodesCount = (node = root, max = root.val) => {
if (!node) return 0;
const nextMax = Math.max(max, node.val);
const left = getGoodNodesCount(node.left, nextMax);
const right = getGoodNodesCount(node.right, nextMax);
return left + right + (nextMax === node.val ? 1 : 0);
};
return getGoodNodesCount();
};