1980. Find Unique Binary String
Description
Given an array of strings nums
containing n
unique binary strings each of length n
, return a binary string of length n
that does not appear in nums
. If there are multiple answers, you may return any of them.
Example 1:
Input: nums = ["01","10"] Output: "11" Explanation: "11" does not appear in nums. "00" would also be correct.
Example 2:
Input: nums = ["00","01"] Output: "11" Explanation: "11" does not appear in nums. "10" would also be correct.
Example 3:
Input: nums = ["111","011","001"] Output: "101" Explanation: "101" does not appear in nums. "000", "010", "100", and "110" would also be correct.
Constraints:
n == nums.length
1 <= n <= 16
nums[i].length == n
nums[i]
is either'0'
or'1'
.- All the strings of
nums
are unique.
Solutions
Solution: Backtracking
- Time complexity: O(n2)
- Space complexity: O(n)
JavaScript
js
/**
* @param {string[]} nums
* @return {string}
*/
const findDifferentBinaryString = function (nums) {
const size = nums[0].length;
const backtracking = (current = '') => {
if (current.length === size) {
if (nums.includes(current)) return '';
return current;
}
const result = backtracking(`${current}0`);
if (result) return result;
return backtracking(`${current}1`);
};
return backtracking();
};