961. N-Repeated Element in Size 2N Array
Description
You are given an integer array nums with the following properties:
nums.length == 2 * n.numscontainsn + 1unique elements.- Exactly one element of
numsis repeatedntimes.
Return the element that is repeated n times.
Example 1:
Input: nums = [1,2,3,3] Output: 3
Example 2:
Input: nums = [2,1,2,5,3,2] Output: 2
Example 3:
Input: nums = [5,1,5,2,5,3,5,4] Output: 5
Constraints:
2 <= n <= 5000nums.length == 2 * n0 <= nums[i] <= 104numscontainsn + 1unique elements and one of them is repeated exactlyntimes.
Solutions
Solution: Hash Table
- Time complexity: O(n)
- Space complexity: O(n)
JavaScript
js
/**
* @param {number[]} nums
* @return {number}
*/
const repeatedNTimes = function (nums) {
const n = nums.length;
for (let index = 2; index < n; index++) {
const num = nums[index];
if (num === nums[index - 1] || num === nums[index - 2]) {
return num;
}
}
return nums[n - 1];
};